Count the Zeros

 Count the Zeros 

Given an array of size N consisting of only 0's and 1's ,which is sorted in such a manner that all the 1's are placed first and then they are followed by all the 0's. You have to find  the count of all the 0's.
 

Input:
The first line of input contains an integer T denoting the number of test cases. Then T test cases follow. 
The first line of each test case contains an integer N, where N is the size of the array A[ ].
The second line of each test case contains N space separated integers of all 1's follwed by all the 0's, denoting elements of the array A[ ].


Output:
Print out the number of 0's in the array. 
 

Constraints:
1 <= T <= 100
1 <= N <= 30
0 <= A[i] <= 1
 

Example :

Input:
3
12
1 1 1 1 1 1 1 1 1 0 0 0 
5
0 0 0 0 0
6
1 1 1 1 1 1


Output:
3
5
0
 

Expected Complexity:

O(logN)


SOLUTION:

t=int(input())

for i in range (t):

    n=int(input())

    p=list(map(int,input().split()))

    print(p.count(0))

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