Number of occurrence (GFG)

 Given a sorted array A of size N and a number X, you need to find the number of occurrences of X in A.

Input:
The first line of input contains an integer T denoting the number of test cases. T testcases follow. Each testcase contains two lines of input: The first line contains N and X(element whose occurrence needs to be counted). The second line contains the elements of the array separated by spaces.

Output:
For each testcase, print the count of the occurrences of X in the array, if count is zero then print -1.

Constraints:
1 ≤ T ≤ 100
1 ≤ N ≤ 105
1 ≤ A[i] ≤ 103
1 <= X <= 103

Example:
Input:
2
7 2
1 1 2 2 2 2 3
7 4
1 1 2 2 2 2 3
Output:
4
-1

Explanation:
Testcase 1: 2 occurs 4 times in 1 1 2 2 2 2 3
Testcase 2: 4 is not present in 1 1 2 2 2 2 3

SOLUTION:

t=int(input())

for i in range(t):

    x,y = map(int,input().split())

    li = list(map(int,input().split()))

    if y in li:

        print(li.count(y))

    else:

        print('-1')

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