Last index of One

 Last index of One 

Given a string S consisting only '0's and '1's,  print the last index of the '1' present in it.

Input:
First line of the input contains the number of test cases T, T lines follow each containing a stream of characters.

Output:
Corresponding to every test case, output the last index of 1. If 1 is not present, print "-1" (without quotes).

Constraints:
1 <= T <= 110
1 <= |S| <= 106

Example:
Input:
2
00001
0
Output:
4
-1

Explanation:
Testcase 1: Last index of  1 in given string is 4.
Testcase 2: Since, 1 is not present, so output is -1.


SOLUTION:

t=int(input())

for i in range (t):

    s=input()

    c=-1

    for j in range(0,len(s)):

        if s[j]=="1":

            c=j

    print (c)

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